Orifice flow theory: What is the theoretical jet velocity at a section having head H (ideal, no losses)?

Difficulty: Easy

Correct Answer: v = sqrt(2 * g * H)

Explanation:


Introduction / Context:
Torricelli's theorem gives the ideal (lossless) efflux velocity under a head H as if a particle fell freely through that head. It underpins orifice and nozzle calculations before applying discharge and velocity coefficients for real flows.


Given Data / Assumptions:

  • Incompressible fluid.
  • Negligible elevation differences aside from head H.
  • No losses (ideal analysis).


Concept / Approach:
Bernoulli between the free surface and the jet section with atmospheric pressure on both locations reduces to v^2/(2g) = H, so v = sqrt(2 * g * H). Real jets use v = Cv * sqrt(2 * g * H) with Cv < 1.


Step-by-Step Solution:

Apply Bernoulli: (p/ρg + z + v^2/(2g)) constant.Atmospheric pressure cancels; surface velocity ~ 0.Thus v^2/(2g) = H ⇒ v = sqrt(2gH).


Verification / Alternative check:
Dimensional check: g has m/s^2, H has m; product gives m^2/s^2; square root gives m/s as required.


Why Other Options Are Wrong:

  • 2g*H: Missing square root; has wrong units.
  • sqrt(H/(2g)): Inverts the relation.
  • H/(2g): Again wrong units (seconds^2 per meter).


Common Pitfalls:
Forgetting to take the square root; confusing head at vena contracta with upstream head; mixing up Cv and Cd.


Final Answer:
v = sqrt(2 * g * H)

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