Floating bodies – Stability criterion using metacentre A floating body is said to be not in (stable) equilibrium if its metacentre M lies below its centre of gravity G. Do you agree with this statement?

Difficulty: Easy

Correct Answer: Agree

Explanation:


Introduction:
For floating bodies, small-angle stability is evaluated using the metacentric height GM, where G is the centre of gravity and M is the metacentre. The sign of GM determines the nature of equilibrium, which is critical for ship design, buoys, and pontoon platforms.


Given Data / Assumptions:

  • Small angular displacement (initial stability).
  • Homogeneous liquid; body floats partially submerged.
  • Quasi-static conditions (no waves or dynamic effects).


Concept / Approach:

For small heel angles, the restoring moment per unit heel angle is proportional to GM. If GM > 0 (M above G), a restoring moment returns the body to its original position (stable). If GM = 0, the body exhibits neutral equilibrium. If GM < 0 (M below G), an overturning moment increases the displacement—this is unstable (i.e., not in stable equilibrium). Thus, the statement is correct.


Step-by-Step Solution:

Step 1: Define GM = distance from G to M measured along the vertical through G.Step 2: Relate sign of GM to stability: positive → stable, zero → neutral, negative → unstable.Step 3: Given M below G implies GM negative; hence the body is not in stable equilibrium.


Verification / Alternative check:

Ship stability textbooks use the righting arm GZ ≈ GM * sin(theta) for small theta. If GM is negative, the righting arm reverses sign, indicating capsizing tendency, confirming instability.


Why Other Options Are Wrong:

Disagree: Contradicts the metacentric height criterion.Angle or density caveats: Initial stability result holds without those extra restrictions.


Common Pitfalls:

Confusing small-angle (initial) stability with large-angle behavior; GM is strictly an initial stability parameter but suffices for the statement posed.


Final Answer:

Agree

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