Archimedes’ law of buoyancy – magnitude of the buoyant force For a body immersed wholly or partially in a fluid at rest, the buoyant force acting on the body is always __________ the weight of the fluid displaced by the body.

Difficulty: Easy

Correct Answer: equal to

Explanation:


Introduction:
Buoyancy is a cornerstone concept in fluid mechanics and naval architecture. The question tests the precise statement of Archimedes’ law regarding the magnitude of the buoyant force on a body immersed in a static fluid. Understanding this equality is essential for predicting floatation, apparent weight loss, and stability analyses.


Given Data / Assumptions:

  • Fluid at rest (hydrostatics).
  • Body may be fully or partially submerged.
  • Gravitational field is uniform; fluid density is constant.
  • No fluid motion–induced dynamic effects (no lift or drag).


Concept / Approach:

Archimedes’ principle states: the buoyant force on a submerged body equals the weight of the fluid displaced by that body. This arises from integrating the hydrostatic pressure over the body's surface. Pressure increases with depth, producing a net upward resultant equal to rho * g * V_displaced, whose weight is rho * g * V_displaced. Hence, the magnitude of buoyant force equals the weight of fluid displaced, independent of the body's own material (though floatation depends on comparing forces).


Step-by-Step Solution:

Step 1: Recognize hydrostatic pressure p = p0 + rho * g * h acts normally on surfaces.Step 2: Integrate pressure over the body surface; vertical components at different depths do not cancel.Step 3: Net upward force obtained equals rho * g * V_displaced, which is the weight of the displaced fluid.Step 4: Conclude equality: F_buoyancy = weight of displaced fluid.


Verification / Alternative check:

For a floating object in equilibrium, weight of body W equals buoyant force, so W = rho * g * V_displaced. For a fully submerged, tethered body, the scale reading equals W − F_buoyancy, again showing F_buoyancy equals the displaced fluid weight irrespective of the body's density in still fluid.


Why Other Options Are Wrong:

Less than / more than: Contradict the exact equality from Archimedes’ law.Dependent on body shape only: Shape affects displaced volume but not the equality relation.Zero unless floating: Even a fully submerged object experiences buoyancy.


Common Pitfalls:

Confusing buoyant force with net force; net force depends on comparing buoyancy with the object’s weight. Also, mixing hydrostatic buoyancy with dynamic lift that occurs in moving fluids.


Final Answer:

equal to

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