Difficulty: Easy
Correct Answer: equal to
Explanation:
Introduction:
Buoyancy is a cornerstone concept in fluid mechanics and naval architecture. The question tests the precise statement of Archimedes’ law regarding the magnitude of the buoyant force on a body immersed in a static fluid. Understanding this equality is essential for predicting floatation, apparent weight loss, and stability analyses.
Given Data / Assumptions:
Concept / Approach:
Archimedes’ principle states: the buoyant force on a submerged body equals the weight of the fluid displaced by that body. This arises from integrating the hydrostatic pressure over the body's surface. Pressure increases with depth, producing a net upward resultant equal to rho * g * V_displaced, whose weight is rho * g * V_displaced. Hence, the magnitude of buoyant force equals the weight of fluid displaced, independent of the body's own material (though floatation depends on comparing forces).
Step-by-Step Solution:
Verification / Alternative check:
For a floating object in equilibrium, weight of body W equals buoyant force, so W = rho * g * V_displaced. For a fully submerged, tethered body, the scale reading equals W − F_buoyancy, again showing F_buoyancy equals the displaced fluid weight irrespective of the body's density in still fluid.
Why Other Options Are Wrong:
Less than / more than: Contradict the exact equality from Archimedes’ law.Dependent on body shape only: Shape affects displaced volume but not the equality relation.Zero unless floating: Even a fully submerged object experiences buoyancy.
Common Pitfalls:
Confusing buoyant force with net force; net force depends on comparing buoyancy with the object’s weight. Also, mixing hydrostatic buoyancy with dynamic lift that occurs in moving fluids.
Final Answer:
equal to
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