Difficulty: Easy
Correct Answer: all of the above
Explanation:
Introduction:
Water hammer is the rapid pressure rise or surge that occurs when flowing liquid is forced to stop or change direction suddenly. This question tests which physical factors govern the magnitude of that surge, a crucial topic in civil and mechanical pipeline design.
Given Data / Assumptions:
Concept / Approach:
The classical Joukowsky relation gives the peak pressure rise: Δp = ρ * a * ΔV where a is the wave speed. The wave speed depends on both fluid bulk modulus and pipe-wall elasticity. Closure time relative to wave travel time sets how fully the Joukowsky rise develops.
Step-by-Step Solution:
1) Recognize that stiffer walls and less compressible liquids yield larger wave speed a.2) Larger a makes Δp greater for the same velocity change.3) Faster valve closure (small closure time) increases ΔV per wave reflection, approaching the full Joukowsky surge.4) Hence all three—pipe elasticity, fluid compressibility, and closure speed—affect magnitude.
Verification / Alternative check:
Surge analysis software and field records show that installing air vessels or using slow-closure valves reduces peak surge by altering ΔV and the effective compressibility of the system.
Why Other Options Are Wrong:
Common Pitfalls:
Ignoring pipe supports and entrapped air; both modify effective wave speed and observed surge.
Final Answer:
all of the above
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