Curioustab
Aptitude
General Knowledge
Verbal Reasoning
Computer Science
Interview
Aptitude
General Knowledge
Verbal Reasoning
Computer Science
Interview
Home
»
Mechanical Engineering
»
Heat Transfer, Refrigeration and Air Conditioning
Thermal conductivity of a material may be defined as the
quantity of heat flowing in one second through a slab of the material of area 1 cm2 and thickness 1 cm when its faces differ in temperature by 1° C
quantity of heat flowing in one second through one cm of material when opposite faces are maintained at a temperature difference of 1° C
heat conducted in unit time across unit area through unit thickness when a temperature difference of unity is maintained between opposite faces
all of the above
Correct Answer:
all of the above
← Previous Question
Next Question→
More Questions from
Heat Transfer, Refrigeration and Air Conditioning
When the lower temperature of a refrigerating machine is fixed, then the coefficient of performance can be improved by
A one tonne refrigerating machine means that
The cooling of air, without any change in its specific humidity, is known as sensible cooling.
The ratio of the actual mass of water vapour in a unit mass of dry air to the mass of water vapour in the same mass of dry air when it is saturated at the same temperature and pressure, is called
The air cooling system mostly used in transport type aircrafts is
The evaporator used in house-hold refrigerators is
The capacity of the cooling tower and spray ponds __________ as the wet bulb temperature of air decreases.
Dehydration is the process of removing water vapour from the surrounding air.
If the evaporator temperature is kept constant, the coefficient of performance of a refrigeration cycle __________ with the increase in condenser temperature.
The heat transfer by conduction through a thick cylinder(Q) is given by (where T1 = Higher temperature, T2 = Lower temperature, r1 = Inside radius, r2 = Outside radius, l = Length of cylinder, and k = Thermal conductivity)
Discussion & Comments
No comments yet. Be the first to comment!
Name:
Comment:
Post Comment
Join Discussion
Discussion & Comments