Difficulty: Easy
Correct Answer: 2 m r^2 / 3
Explanation:
Introduction / Context:
Standard mass moment of inertia formulas are essential in rotational dynamics. A thin spherical shell concentrates mass at a constant radius, changing its inertia compared with a solid sphere.
Given Data / Assumptions:
Concept / Approach:
Known results: Solid sphere about diameter: I = 2 m r^2 / 5. Thin spherical shell about diameter: I = 2 m r^2 / 3. The shell’s mass is farther from the center compared with a solid sphere, hence the larger coefficient.
Step-by-Step Solution:
Use standard result for a thin shell: I_diameter = 2 m r^2 / 3. No integration needed in an exam setting because it is a tabulated formula.
Verification / Alternative check:
Relative comparison: 2/3 ≈ 0.667 is greater than 2/5 = 0.4, reflecting the mass being distributed at radius r rather than throughout the volume.
Why Other Options Are Wrong:
m r^2 / 3: too small; not a standard result. 2 m r^2 / 5: that is for a solid sphere, not a thin shell. 3 m r^2 / 5 and m r^2: do not correspond to any standard spherical model about a diameter.
Common Pitfalls:
Mixing up solid vs thin-shell formulas; always recall shell has larger inertia for the same m and r.
Final Answer:
2 m r^2 / 3
Discussion & Comments