Resultant of Two Equal Forces — Magnitude Formula Two equal forces each of magnitude P act at an angle θ to each other. What is the magnitude of their resultant?

Difficulty: Easy

Correct Answer: 2 P cos(θ/2)

Explanation:


Introduction / Context:
Vector addition of two forces is a staple of statics and dynamics. For equal magnitudes with angle θ between them, the resultant has a compact expression that is widely used in engineering and physics.


Given Data / Assumptions:

  • Force magnitudes: P and P.
  • Angle between forces: θ.


Concept / Approach:
Use the law of cosines for vectors: R^2 = P^2 + P^2 + 2 P P cos θ. Then take the square root to obtain R. Trigonometric half-angle identities lead to a simple form involving cos(θ/2).


Step-by-Step Solution:

R^2 = 2P^2 (1 + cos θ). Use identity: 1 + cos θ = 2 cos^2(θ/2). Hence R = √(2P^2 * 2 cos^2(θ/2)) = 2P cos(θ/2).


Verification / Alternative check:
Special cases: θ = 0 ⇒ R = 2P (collinear same direction). θ = 180° ⇒ R = 0 (equal and opposite), consistent with formula since cos 90° = 0.


Why Other Options Are Wrong:
Forms with sin, tan, or cot of θ/2 do not satisfy the cosine-law derivation and fail at boundary checks (e.g., θ = 0 or 180°).


Common Pitfalls:
Forgetting the half-angle identity or misapplying parallelogram/triangle construction with wrong included angle.


Final Answer:
2 P cos(θ/2).

More Questions from Engineering Mechanics

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion