Ideal machine check — work and efficiency A lifting machine raises a 1000 N load through 0.2 m using an effort of 200 N through 1.0 m. Is this machine ideal (100% efficient)?

Introduction / Context:
An ideal machine has no losses, so input work equals output work and efficiency equals 100%. This question tests your ability to verify ideality by comparing work in and work out.

Given Data / Assumptions:

• Load = 1000 N; load distance = 0.2 m.
• Effort = 200 N; effort distance = 1.0 m.
• No additional losses specified (we compute purely from given values).

Concept / Approach:
Efficiency η = output work / input work. If η = 1 (or 100%), the machine is ideal. Also, for an ideal machine, Mechanical Advantage (M.A.) = Velocity Ratio (V.R.).

Step-by-Step Solution:

Verification / Alternative check:
Because work in equals work out exactly, there are no implied energy losses. This confirms the ideal assumption from the given numbers.

Why Other Options Are Wrong:

• Incorrect: Conflicts with equal input and output work.
• Correct only if friction is ignored: Already implied by equal works; the data shows no loss.
• Correct only if V.R. = 10: Irrelevant; V.R. here is 5.
• Incorrect because M.A. ≠ V.R.: They are equal in this case.

Common Pitfalls:
Mixing up force ratios with work equality; forgetting that efficiency compares energies, not just forces or distances independently.

Final Answer:
Correct