Resultant of forces meeting at a point — compute magnitude from components If several forces act at a point, the magnitude of the single resultant R in terms of the algebraic sums of horizontal and vertical components (ΣH and ΣV) is:

Difficulty: Easy

Correct Answer: R = √( (ΣH)^2 + (ΣV)^2 )

Explanation:


Introduction / Context:
Vector addition of forces is fundamental. When multiple forces act at a point, we commonly resolve them into orthogonal components and then recombine to find a single equivalent resultant force.



Given Data / Assumptions:

  • All forces are concurrent (meet at a single point).
  • Components are resolved along mutually perpendicular axes (horizontal H and vertical V).
  • ΣH and ΣV denote algebraic sums of components.


Concept / Approach:
The resultant of orthogonal components follows the Pythagorean relationship. If R has components (ΣH, ΣV), then the magnitude of R is given by R = sqrt( (ΣH)^2 + (ΣV)^2 ). The direction θ satisfies tan(θ) = ΣV / ΣH.



Step-by-Step Solution:

Resolve each force F_i into H and V components.Add components: ΣH = ΣF_ix and ΣV = ΣF_iy.Compute magnitude: R = √( (ΣH)^2 + (ΣV)^2 ).Optionally find direction: θ = atan2(ΣV, ΣH).


Verification / Alternative check:
Check special case: If ΣH = 0, then R = |ΣV|; if ΣV = 0, then R = |ΣH|. This is consistent with the square root expression.



Why Other Options Are Wrong:

  • (ΣH)^2 + (ΣV)^2 without a square root: Gives the squared magnitude, not the magnitude.
  • (ΣH + ΣV)^2 or ΣH + ΣV: Mixing components algebraically destroys vector nature.
  • √(ΣH + ΣV): Nondimensional and incorrect.


Common Pitfalls:
Forgetting to take the square root; sign errors when summing components; incorrect angle quadrant due to signs of ΣH and ΣV.



Final Answer:
R = √( (ΣH)^2 + (ΣV)^2 )


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