Plane stress relations — maximum shear stress: The maximum shear stress in plane stress equals what fraction of the algebraic difference between maximum and minimum normal stresses?

Difficulty: Easy

Correct Answer: one-half

Explanation:


Introduction:
Mohr's circle for plane stress provides direct relations among principal stresses and maximum shear stress. This question checks your command of that geometric interpretation.

Given Data / Assumptions:

  • Plane stress with principal stresses σ1 and σ2.
  • Linear elasticity and small deformations.


Concept / Approach:
On Mohr's circle, the radius equals (σ1 − σ2)/2 and represents the maximum shear stress τ_max in plane stress. Hence τ_max = (σ_max − σ_min)/2.

Step-by-Step Solution:

Define principal stresses: σ_max = σ1, σ_min = σ2Mohr’s circle radius: R = (σ1 − σ2)/2Therefore τ_max = R = (σ_max − σ_min)/2


Verification / Alternative check:
Stress transformation equations also yield the same result when maximizing shear with respect to angle, confirming the half-difference relationship.

Why Other Options Are Wrong:

  • Equal to or twice: Overestimate τ_max.
  • One-fourth or three-fourths: Arbitrary fractions not supported by the transformation equations.


Common Pitfalls:
Confusing average stress (σ_avg) with radius; mixing up shear in 3D with plane-stress results.

Final Answer:

one-half

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