Longest pencil in a box (space diagonal): A rectangular box has dimensions 8 cm × 6 cm × 2 cm. What is the maximum length of a pencil that can fit inside it?

Difficulty: Easy

Correct Answer: 2 √26 cm

Explanation:


Introduction / Context:
The longest object that fits inside a rectangular box equals its space diagonal. This tests 3D Pythagoras across three perpendicular edges.


Given Data / Assumptions:

  • Dimensions: 8 cm, 6 cm, 2 cm
  • Max length L = √(8^2 + 6^2 + 2^2)


Concept / Approach:

  • Apply space diagonal formula for a cuboid.


Step-by-Step Solution:

L = √(8^2 + 6^2 + 2^2) = √(64 + 36 + 4) = √104.Since 104 = 4 * 26, L = √(4*26) = 2√26 cm.


Verification / Alternative check:

Approximate: √26 ≈ 5.099 ⇒ 2√26 ≈ 10.198 cm.


Why Other Options Are Wrong:

  • 2√13 cm: Uses half the sum inside the root incorrectly.
  • 2√14 cm: Incorrect decomposition.
  • 10√2 cm: Corresponds to √(8^2 + 6^2) only, ignoring the 2 cm height.


Common Pitfalls:

  • Using face diagonal instead of space diagonal.
  • Arithmetic slips inside the square root.


Final Answer:

2 √26 cm

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