Father–son linear system: A man is five times as old as his son. Four years later, the sum of their ages will be 56. Find the son’s present age.

Difficulty: Easy

Correct Answer: 8 years

Explanation:


Introduction / Context:
We combine a present multiplicative relation with a future sum. Express the father’s age in terms of the son’s age, then apply the future sum to solve for the son directly.


Given Data / Assumptions:

  • Let present ages be M and S
  • M = 5S
  • (M + 4) + (S + 4) = 56


Concept / Approach:
Substitute M = 5S into the future-sum equation and solve for S. This yields the son’s current age immediately.


Step-by-Step Solution:

5S + S + 8 = 56 ⇒ 6S = 48 ⇒ S = 8


Verification / Alternative check:
Father now = 40. After 4 years: 44 and 12; sum = 56 ✓.


Why Other Options Are Wrong:
12, 5, and 6 do not satisfy both constraints simultaneously.


Common Pitfalls:
Adding 4 to only one of them; both ages advance by 4 years.


Final Answer:
8 years

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