Difficulty: Easy
Correct Answer: Agree – zero (no loss of kinetic energy)
Explanation:
Introduction / Context:‘‘Elastic’’ and ‘‘inelastic’’ classify collisions based on kinetic energy behavior. In ideal elastic impacts, kinetic energy is conserved; in inelastic impacts, some kinetic energy transforms into other forms.
Given Data / Assumptions:
Concept / Approach:For e = 1, both linear momentum (along the line of impact) and kinetic energy are conserved. Thus the total kinetic energy before equals that after impact.
Step-by-Step Solution:
State conservation: Σp_before = Σp_after and ΣKE_before = ΣKE_after.With e = 1, relative velocity of separation equals relative velocity of approach, a hallmark of elastic behavior.Therefore, loss of kinetic energy = 0.Verification / Alternative check:Classic 1D two-body formulas for elastic collision show KE_before − KE_after = 0; numerical examples with equal masses show a perfect velocity swap and identical total KE.
Why Other Options Are Wrong:
Common Pitfalls:Confusing real collisions (often slightly inelastic) with the idealized, perfectly elastic case used in theory.
Final Answer:Agree – zero loss of kinetic energy
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