Metacentric height from transverse load shift on a ship A load of magnitude w is moved transversely by a distance d across the deck of a ship of displacement W, causing it to heel by an angle θ (small). Determine the metacentric height (GM) from these quantities.
-
AGM = (W * d) / (w * tan θ)
-
BGM = (w * d) / (W * tan θ)
-
CGM = (w * tan θ) / (W * d)
-
DGM = (W * tan θ) / (w * d)
Answer
Correct Answer: GM = (w * d) / (W * tan θ)
Explanation
Introduction / Context:Transverse stability of ships is characterized by the metacentric height GM. A convenient onboard test uses a known weight shift across the deck to induce a small heel angle; from the observed angle, GM can be computed.
Given Data / Assumptions:
- Ship displacement (weight) = W.
- Movable load = w shifted transversely by distance d.
- Heel angle θ is small (tan θ ≈ θ in radians), ensuring metacentric theory validity.
Concept / Approach:Equate the heeling moment produced by the load shift to the righting moment provided by GM. Heeling moment = w * d. Righting moment for small angles = W * GM * tan θ. Setting them equal yields GM = (w * d) / (W * tan θ).
Step-by-Step Solution:
Compute heeling moment: M_h = w * d.Righting moment: M_r = W * GM * tan θ.Equate M_h = M_r → W * GM * tan θ = w * d.Solve: GM = (w * d) / (W * tan θ).Verification / Alternative check:Dimensional check: GM has dimensions of length; (w/W) is dimensionless; d/ tan θ has length → consistent.
Why Other Options Are Wrong:Options (a), (c), and (d) invert factors improperly, giving wrong dimensions or scaling.
Common Pitfalls:Using degrees directly inside tan without conversion when computing numerically; applying the formula at large heel angles where metacentric theory is invalid.
Final Answer:GM = (w * d) / (W * tan θ)