Lap splicing in compression members: The lap length shall not be less than bar_dia * (permissible_stress / (5 * bond_stress)) or which minimum value expressed in bar diameters, whichever is greater?
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A12 bar diameters
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B18 bar diameters
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C24 bar diameters
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D30 bar diameters
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E36 bar diameters
Answer
Correct Answer: 24 bar diameters
Explanation
Introduction / Context:Lap splices in compression must safely transfer force between bars through bond with concrete. Codes specify a calculated lap length and also a minimum bar diameter multiple to cover variability in workmanship and conditions.
Given Data / Assumptions:
- Compression member with lapped longitudinal bars.
- Design stresses and bond stresses per standard practice.
- Requirement: adopt the larger of calculated or minimum lap.
Concept / Approach:The calculated lap uses permissible stress and bond stress values; however, a minimum of 24φ (φ = bar diameter) is typically specified for compression laps to ensure adequate embedment and confinement length even when calculated values are small.
Step-by-Step Solution:Compute L_calc = φ * (permissible_stress / (5 * bond_stress)).Compare with L_min = 24φ.Provide lap length = max(L_calc, 24φ) within a zone of adequate transverse reinforcement.
Verification / Alternative check:Confinement via closer ties in splice regions enhances bond behavior; design guides consistently adopt 24φ as the baseline for compression laps in normal conditions.
Why Other Options Are Wrong:
- 12φ and 18φ: usually insufficient for reliable compression splices.
- 30φ or 36φ: conservative but not the commonly mandated minimum for compression laps in ordinary conditions.
Common Pitfalls:Placing splices at highly stressed sections, inadequate tie spacing, and ignoring cover limitations which reduce bond effectiveness.
Final Answer:24 bar diameters.