Trend of latent heat near the critical point:\nHow does the heat of vaporisation change with pressure, and what happens at the critical point?

Difficulty: Easy

Correct Answer: Both decreases with pressure and becomes zero at the critical point

Explanation:


Introduction / Context:
Phase-change energetics are vital for boilers, condensers, and power cycles. The latent heat of vaporisation reflects the energy required to separate liquid and vapor phases; its behavior with pressure reveals what happens as a fluid approaches the critical state.



Given Data / Assumptions:

  • Pure fluid undergoing equilibrium vaporisation along the saturation curve.
  • Critical point: liquid and vapor phases become indistinguishable.


Concept / Approach:
The Clausius–Clapeyron relation shows latent heat λ ∝ T * Δv * (dP_sat/dT). As pressure increases toward the critical pressure, the specific volume difference Δv = v_g − v_l shrinks. Consequently, λ decreases and must reach zero at the critical point where Δv → 0.



Step-by-Step Reasoning:

Increase pressure → move up saturation curve → liquid and vapor densities converge.As Δv decreases, λ correspondingly decreases.At the critical point, Δv = 0 → λ = 0.


Verification / Alternative check:
Steam tables show the latent heat of water declining with pressure and vanishing at the critical point (~22.06 MPa), validating the trend.



Why Other Options Are Wrong:

  • Increase or remain constant: Contradicted by data and theory.
  • Only “becomes zero” without noting the continuous decrease omits the trend.


Common Pitfalls:
Confusing latent heat with sensible heat; assuming a constant latent heat across pressures.



Final Answer:
Both decreases with pressure and becomes zero at the critical point

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