Difficulty: Easy
Correct Answer: False
Explanation:
Introduction / Context:Understanding the internal RAM layout of the 8051 is vital for stack placement, register bank usage, and bit-addressable operations. The lower 128 bytes are divided into specific regions, not all of which are general-purpose.
Given Data / Assumptions:
Concept / Approach:Lower RAM map: 00h–1Fh = register banks (32 bytes), 20h–2Fh = bit-addressable area (16 bytes), 30h–7Fh = general-purpose RAM (80 bytes). The stack typically grows within this GPR area unless relocated by the programmer. Therefore, the “last 96 locations” claim is incorrect; it is actually 80 bytes (30h–7Fh).
Step-by-Step Solution:
1) Compute GPR size: 0x7F − 0x30 + 1 = 0x50 = 80 bytes.2) Recognize stack resides in GPR region by default (SP starts at 07h).3) Conclude the statement claiming 96 bytes is false.Verification / Alternative check:Refer to any 8051 memory map diagram showing the partitions of lower RAM and SFR space.
Why Other Options Are Wrong:
Common Pitfalls:Confusing lower RAM size (128 bytes) with the GPR subset; miscounting the bit-addressable area as general-purpose.
Final Answer:False
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