Java threads: calling run() directly vs starting a new thread.\n\nclass MyThread extends Thread {\n public static void main(String[] args) {\n MyThread t = new MyThread();\n t.run();\n }\n public void run() {\n for (int i = 1; i < 3; ++i) {\n System.out.print(i + "..");\n }\n }\n}

Introduction / Context:
The distinction between Thread.start() and Thread.run() is fundamental in Java concurrency. start() creates a new thread of execution and then invokes run() on that new thread. Calling run() directly executes the method on the current thread (here, main), with no concurrency.

Given Data / Assumptions:

• A class extends Thread and overrides run().
• main creates MyThread and calls t.run() directly.
• The loop prints i from 1 to 2 inclusive.

Concept / Approach:
The loop bounds are i = 1; i < 3; ++i → values 1 and 2. Because run() is called like a normal method, it executes on the main thread and simply prints text; there is no second thread involved, but the output tokens are unaffected.

Step-by-Step Solution:

Verification / Alternative check:
If t.start() were used, the same text would print, but on another thread and with potential interleavings with other concurrent output.

Why Other Options Are Wrong:

• Compilation errors do not exist in this snippet.
• 1..2..3.. would require i <= 3 or a different bound.
• “No output” contradicts the loop execution.

Common Pitfalls:
Confusing run() for start(); expecting new-thread behavior without calling start().

Final Answer:
1..2..