Multi-year weekday shift from a known Jan 1: If it was Sunday on January 1, 2006, what was the day of the week on January 2, 2010?

Difficulty: Medium

Correct Answer: Saturday

Explanation:


Introduction / Context:
Across several years, we sum yearly shifts: +1 for each common year and +2 for each leap year encountered. After reaching the target year’s same date, we add the remaining day offset to reach the exact target date.


Given Data / Assumptions:

  • Jan 1, 2006 = Sunday.
  • We need Jan 2, 2010.
  • Year-by-year: 2006 (+1), 2007 (+1), 2008 (leap, +2), 2009 (+1).


Concept / Approach:
Compute the net shift to Jan 1, 2010, then step one more day to Jan 2, 2010.


Step-by-Step Solution:

Total to Jan 1, 2010 = 1 + 1 + 2 + 1 = +5 ⇒ Sunday → Friday.Jan 2, 2010 = Friday + 1 = Saturday.


Verification / Alternative check:
Modulo arithmetic: 365 ≡ 1, 366 ≡ 2 (mod 7); accumulated = 5; then +1 day.


Why Other Options Are Wrong:
Thursday/Sunday/Friday reflect partial steps; only Saturday matches full accumulation.


Common Pitfalls:
Forgetting to add the extra one day from Jan 1 to Jan 2 after computing the multi-year shift.


Final Answer:
Saturday

More Questions from Calendar

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion