Difficulty: Easy
Correct Answer: Thrice the average demand (3.0 times)
Explanation:
Introduction / Context:
Sanitary sewers must carry variable flows. Even in dry weather, diurnal patterns and stochastic variations cause peaks above the average. Designers therefore apply a peaking factor to the average DWF to obtain a practical design discharge for hydraulic sizing.
Given Data / Assumptions:
Concept / Approach:
Standard practice often uses approximately 3 times the average DWF (for small to medium systems) to cover daily peaks, upstream synchronization, and uncertainties. Larger trunk mains may justify lower factors based on empirical formulas, but 3.0 is a frequently cited benchmark in examination problems.
Step-by-Step Solution:
Compute average DWF from unit contributions.Apply peaking factor ≈ 3 to obtain design discharge.Check velocity criteria (self-cleansing and non-scouring) at both minimum and peak flows.
Verification / Alternative check:
Alternative peaking factor relations (for example population dependent) often yield values near 2.5–3.0 for many service areas, corroborating the 3.0 choice in typical exam settings.
Why Other Options Are Wrong:
1.0–2.0: may under-size upstream sewers resulting in surcharge.4.0–5.0: overly conservative for DWF and could be reserved for special cases or combined systems.
Common Pitfalls:
Final Answer:
Thrice the average demand (3.0 times)
Discussion & Comments