Laplace transform practice: For the input forcing function X(t) = 2 t^2 (for t ≥ 0), what is its Laplace transform?

Difficulty: Easy

Correct Answer: 4 / s^3

Explanation:

Introduction / Context:Laplace transforms convert time-domain signals into the s-domain for system analysis and control design. Powers of time are common test inputs for checking transform fluency.

Given Data / Assumptions:

  • X(t) = 2 t^2 for t ≥ 0.
  • Standard transform: L{t^n} = n! / s^(n+1).

Concept / Approach:Use the known transform of t^n and scale by constants. For n = 2, L{t^2} = 2! / s^3 = 2 / s^3. Multiplying by the constant 2 gives the final result.

Step-by-Step Solution:Start with L{t^n} = n! / s^(n+1).Set n = 2 → L{t^2} = 2 / s^3.Multiply by 2 (from 2 t^2) → 2 * (2 / s^3) = 4 / s^3.

Verification / Alternative check:Differentiate the known result L{t} = 1/s^2 with respect to s (using properties) to recover L{t^2} and confirm.

Why Other Options Are Wrong:

  • 2/s^2 or 4/s^2: incorrect power of s; corresponds to L{t} forms.
  • 2/s^3: misses the factor of 2 from the input amplitude.
  • 2/s^4: corresponds to t^3 behavior.

Common Pitfalls:Forgetting the constant multiplier or misapplying the exponent in s.

Final Answer:4 / s^3

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