Compute the inductive reactance X_L of a 2 H inductor operating at 60 Hz. Provide the nearest whole-ohm value.

Introduction / Context:Inductive reactance quantifies how an inductor opposes AC. It increases with both inductance and frequency. Quick calculations of X_L are essential in designing filters, chokes, and setting impedance levels in power and signal circuits.

Given Data / Assumptions:

• L = 2 H (henries).
• f = 60 Hz (mains frequency in many regions).
• Ideal inductor; standard formula for X_L applies.

Concept / Approach:The standard relationship is X_L = 2 * pi * f * L. Units: X_L in ohms when f is in hertz and L in henries. The result typically rounds to the nearest ohm for component selection and approximate analysis.

Step-by-Step Solution:

Verification / Alternative check:Use approximate pi = 3.14: X_L ≈ 2 * 3.14 * 60 * 2 = 753.6 Ω, which rounds to 754 Ω, confirming the calculation.

Why Other Options Are Wrong:

Common Pitfalls:Forgetting the factor 2 * pi, mixing up inductive with capacitive reactance, or rounding too early leading to large errors.

Final Answer:754 Ohm.