Series RLC behavior relative to resonance: when a series RLC circuit operates at a frequency above its resonant frequency, it behaves most like which simpler series circuit?

Difficulty: Easy

Correct Answer: series RL circuit

Explanation:


Introduction / Context:
Series RLC circuits transition from capacitive to inductive behavior as frequency sweeps through resonance. Recognizing which element “dominates” above or below resonance is crucial for filter design and understanding impedance and phase.


Given Data / Assumptions:

  • Ideal series R, L, and C components.
  • Single-frequency sinusoidal steady state.
  • Resonant frequency fr where X_L = X_C.


Concept / Approach:
Below resonance, capacitive reactance magnitude exceeds inductive reactance (|X_C| > |X_L|), so the net reactance is capacitive; the circuit resembles an RC behavior. At resonance, X_L = X_C and the impedance is purely resistive (Z ≈ R). Above resonance, |X_L| > |X_C|, so the net reactance is inductive; the circuit behaves like an RL network with inductive phase characteristics.


Step-by-Step Solution:

1) Define resonance: X_L = 2 * pi * f * L; X_C = 1 / (2 * pi * f * C).2) For f > fr, X_L increases and X_C decreases → X_L − X_C > 0 (inductive).3) Conclude behavior: series RLC behaves like a series RL circuit above fr.


Verification / Alternative check:
Phasor angle of impedance above resonance is positive (inductive), confirming RL-like behavior; below resonance it is negative (capacitive), RC-like; at resonance it is zero (resistive).


Why Other Options Are Wrong:

Series RC: true below resonance, not above.Below resonance case: the opposite frequency region.Purely resistive: occurs only at resonance, not above.None of the above: unnecessary because series RL is correct.


Common Pitfalls:
Reversing the above/below resonance behaviors; forgetting that at resonance the reactive parts cancel and impedance reduces to R alone.


Final Answer:
series RL circuit.

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