Faraday’s law in practice: If the speed of a straight conductor moving through a uniform magnetic field is increased while field strength and geometry remain the same, how does the induced voltage (emf) change?

Difficulty: Easy

Correct Answer: increase

Explanation:


Introduction / Context:
Generators, sensors, and motion-based energy harvesting rely on electromagnetic induction. Faraday’s law tells us how induced voltage depends on motion. This question checks conceptual understanding of how speed affects induced emf when a conductor cuts magnetic flux lines.


Given Data / Assumptions:

  • Uniform magnetic field, constant flux density.
  • Conductor length and orientation are constant.
  • Only the speed of motion is changed.


Concept / Approach:
For a straight conductor of length L moving at velocity v perpendicular to magnetic flux density B, the induced emf is E = B * L * v. More generally, Faraday’s law states emf is proportional to the rate of change of flux linkage. If everything else is fixed, increasing v increases the rate of flux cutting and therefore increases the induced voltage proportionally.


Step-by-Step Solution:

Recall induced emf relation: E ∝ rate of flux cutting.With B and L fixed, E = B * L * v.Increase v ⇒ E increases linearly.Hence, the induced voltage increases.


Verification / Alternative check:
Generator equations and lab demonstrations (sliding conductor on rails in a magnetic field) show emf rises with speed under constant field conditions and geometry.


Why Other Options Are Wrong:

  • Not be affected / decrease / equal 0 V: All contradict E ∝ v for fixed B and L.


Common Pitfalls:
Forgetting that only the velocity has changed; mixing up induced voltage with induced current (which also depends on circuit resistance and back-effects).


Final Answer:
increase

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