Induction vs. steady sources – Does a dc source produce induced voltage? Statement: “An induced voltage is produced as a result of a dc voltage.”

Difficulty: Easy

Correct Answer: False

Explanation:


Introduction / Context:
Induced voltage (emf) arises from changing magnetic flux linkage. This question draws a line between steady dc conditions and the dynamic changes required for induction, which is crucial when reasoning about transformers and inductors.


Given Data / Assumptions:

  • “Induced voltage” refers to Faraday-law emf: e = − dλ/dt.
  • “dc voltage” means a constant (time-invariant) source after transients have decayed.
  • We consider ideal elements unless otherwise noted.


Concept / Approach:

A constant dc source produces constant currents and constant magnetic flux in steady state (ignoring saturation and temperature drift). Since dλ/dt = 0 in steady state, the induced emf is zero. Only when the current or flux changes—such as at the moment of switching on/off or during a ramp—does induction occur. Therefore, the statement as written (implying steady dc) is false.


Step-by-Step Solution:

1) For t → ∞ with a dc source applied to an inductor, iL becomes constant.2) Magnetic flux Φ ∝ iL is constant → dΦ/dt = 0.3) Induced emf e = −N * dΦ/dt = 0.4) Only during changes (switching transients) does e briefly appear.


Verification / Alternative check:

Transformers do not pass dc: a constant primary current produces no time-varying flux in steady state, so no sustained secondary emf is induced.


Why Other Options Are Wrong:

“True” is incorrect in steady state. “True only if the dc source is very large” is irrelevant—magnitude does not substitute for d/dt. “True only during switching transients” is contextually right, but the statement under test lacks that qualifier; hence the correct evaluation is False.


Common Pitfalls:

Assuming “voltage causes induction” by itself; it is the time variation of flux linkage that matters.


Final Answer:

False.

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