Difficulty: Medium
Correct Answer: decreases.
Explanation:
Introduction:
The Colburn j-factor provides a convenient way to correlate convective heat transfer data: j_H = St * Pr^(2/3). It ties heat transfer to momentum transfer and is widely used in exchanger rating and air-side correlations. Because j_H contains Pr^(2/3), variations in temperature that alter viscosity and thermal diffusivity will influence its value.
Given Data / Assumptions:
Concept / Approach:
Since j_H = St * Pr^(2/3) and, for a given geometry, St correlates primarily with Re, a drop in Pr with temperature tends to reduce j_H. Even though Re may increase as μ decreases, the explicit Pr^(2/3) dependence usually dominates the j_H trend in standard charts, leading to a net decrease with temperature for common fluids over practical ranges.
Step-by-Step Solution:
Note typical property trend: as T rises, μ ↓ and Pr = ν/α often ↓.Recognize j_H’s explicit Pr^(2/3) multiplier.Infer the overall tendency: j_H decreases with rising temperature.
Verification / Alternative check:
Air- and water-side j-factor charts display lower j-values at higher film temperatures for otherwise similar conditions, consistent with Prandtl decreases.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing j_H with Nusselt number alone; property grouping in j_H makes temperature trends more apparent.
Final Answer:
decreases.
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