Difficulty: Easy
Correct Answer: degradation of energy
Explanation:
Introduction / Context:Entropy is a measure of energy dispersion and irreversibility. When entropy increases, less of the system's energy can be converted into useful work. Understanding this connection is vital in power-plant, refrigeration, and process design.
Given Data / Assumptions:
Concept / Approach:
Entropy generation S_gen > 0 accompanies friction, mixing, unrestrained expansion, finite-ΔT heat transfer, and chemical irreversibility. Exergy destruction is T0 * S_gen (per unit time or process), where T0 is ambient temperature. Thus, higher entropy implies lower capacity to do work, i.e., degraded energy quality.
Step-by-Step Solution:
State second law: ΔS_universe = S_gen ≥ 0.Relate exergy loss to entropy generation: X_dest = T0 * S_gen.Interpret physically: more disorder/dispersion → less extractable work.Conclude: entropy increase represents energy degradation (lower availability).Verification / Alternative check:
Turbine with high irreversibility yields larger S_gen and lower actual work versus isentropic ideal; heat exchanger with large temperature differences generates entropy and reduces potential to do work.
Why Other Options Are Wrong:
Availability does not increase with entropy; temperature/pressure changes are not direct indicators of entropy sign; potential energy is unrelated to entropy definition.
Common Pitfalls:
Equating entropy strictly with 'disorder' without linking to work potential; assuming any temperature rise means entropy rise (not necessarily true).
Final Answer:
degradation of energy
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