Uniform current in series circuits: If you know the current at any one point, do you know the current everywhere in that same series loop? Evaluate this statement for an ideal DC series network with no branching.

Introduction / Context:
Consistency of current in series networks is a cornerstone of circuit analysis. This question tests recognition that a series loop provides exactly one path for charge, enforcing the same current through each element.

Given Data / Assumptions:

• Ideal DC conditions with a single closed loop (no parallel branches).
• Lumped elements; wire resistance may be small but forms part of the single path.
• Steady state (no transient capacitive/inductive effects considered).

Concept / Approach:

Kirchhoff’s Current Law (KCL) states that current entering a node equals current leaving it. In a series path, every node connects to exactly two elements, so the same current must flow from element to element. Ohm’s law then determines individual voltage drops based on that same current and each resistance value.

Step-by-Step Solution:

Verification / Alternative check:

Numeric example: with R1 = 1 kΩ and R2 = 3 kΩ in series across 8 V, I = 8 / 4000 = 2 mA flows through both resistors. Voltage drops differ (2 V and 6 V), but current remains 2 mA in each component and wire segment.

Why Other Options Are Wrong:

• Equal resistor values are unnecessary; current equality does not depend on value matching.
• AC steady-state series circuits also have the same current through all series impedances.
• Nonzero wire resistance does not break current continuity; it simply adds to the series impedance.

Common Pitfalls:

Confusing current uniformity with voltage distribution. In series, current is uniform; voltage divides according to resistance or impedance.

Final Answer:

True