Effect of doubling beam width on central deflection A simply supported prismatic beam carries a single concentrated load at midspan. If the beam's width b is doubled (all other parameters unchanged), how does the central deflection change?

Difficulty: Medium

Correct Answer: It becomes 1/2 of the original deflection

Explanation:


Introduction / Context:
Deflection control is a key serviceability requirement. For rectangular sections, the flexural rigidity E * I depends on the geometry, so changing width or depth alters deflection in predictable ways.



Given Data / Assumptions:

  • Simply supported beam, concentrated load P at midspan.
  • Span L, Young’s modulus E, depth h remain constant.
  • Rectangular section with width b.


Concept / Approach:
For a midspan point load on a simply supported beam, the maximum deflection is:
delta_max = P * L^3 / (48 * E * I)For a rectangle, the second moment of area is:
I = b * h^3 / 12Therefore, delta_max is inversely proportional to b when h, E, L, and P are fixed.



Step-by-Step Solution:

Original I_1 = b * h^3 / 12.After doubling width: I_2 = (2 b) * h^3 / 12 = 2 * I_1.Since delta ∝ 1 / I, delta_2 = delta_1 / 2.


Verification / Alternative check:
Check dimensional consistency and observe that increasing section size increases stiffness, reducing deflection proportionally.



Why Other Options Are Wrong:

  • Options a, b, c, e suggest larger deflections, which contradict stiffness increase when width increases.


Common Pitfalls:
Confusing the stronger influence of depth (h appears as h^3) with width (linear effect). Doubling depth would reduce deflection by a factor of 8; doubling width only halves it.



Final Answer:
It becomes 1/2 of the original deflection

More Questions from Strength of Materials

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion