Resultant of two equal coplanar forces: Two equal forces, each of magnitude P, act at a point with an included angle θ between them. Determine the magnitude of their resultant vector.

Difficulty: Easy

Correct Answer: 2P cos(θ/2)

Explanation:


Introduction / Context:
Vector addition of forces is central to statics and dynamics. For the special case of two equal forces, a compact formula relates the resultant to the half-angle between them, simplifying quick hand calculations in design problems.


Given Data / Assumptions:

  • Two coplanar forces of equal magnitude P.
  • Included angle between the forces is θ.
  • Standard Euclidean vector addition applies.


Concept / Approach:

Using the parallelogram (or triangle) law, the magnitude of the resultant R of two forces P and P at angle θ is R = √(P^2 + P^2 + 2P·P cos θ) = √(2P^2 (1 + cos θ)). Apply the half-angle identity 1 + cos θ = 2 cos^2(θ/2) to obtain a simplified expression.


Step-by-Step Solution:

Start: R^2 = 2P^2 (1 + cos θ).Use identity: 1 + cos θ = 2 cos^2(θ/2).Hence R^2 = 4P^2 cos^2(θ/2).Therefore R = 2P cos(θ/2).


Verification / Alternative check:

Limit cases: θ = 0 → R = 2P (forces in the same direction). θ = 180° → R = 0 (equal and opposite). Both confirm the formula.


Why Other Options Are Wrong:

Other trigonometric forms do not satisfy the limiting cases or dimensional reasoning; only option (d) matches vector addition.


Common Pitfalls:

Using sin instead of cos; forgetting to halve the angle; misinterpreting θ as the supplement.


Final Answer:

2P cos(θ/2)

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