Difficulty: Easy
Correct Answer: 2P cos(θ/2)
Explanation:
Introduction / Context:
Vector addition of forces is central to statics and dynamics. For the special case of two equal forces, a compact formula relates the resultant to the half-angle between them, simplifying quick hand calculations in design problems.
Given Data / Assumptions:
Concept / Approach:
Using the parallelogram (or triangle) law, the magnitude of the resultant R of two forces P and P at angle θ is R = √(P^2 + P^2 + 2P·P cos θ) = √(2P^2 (1 + cos θ)). Apply the half-angle identity 1 + cos θ = 2 cos^2(θ/2) to obtain a simplified expression.
Step-by-Step Solution:
Verification / Alternative check:
Limit cases: θ = 0 → R = 2P (forces in the same direction). θ = 180° → R = 0 (equal and opposite). Both confirm the formula.
Why Other Options Are Wrong:
Other trigonometric forms do not satisfy the limiting cases or dimensional reasoning; only option (d) matches vector addition.
Common Pitfalls:
Using sin instead of cos; forgetting to halve the angle; misinterpreting θ as the supplement.
Final Answer:
2P cos(θ/2)
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