Difficulty: Easy
Correct Answer: Q_max = PF * q, where PF is a peak factor dependent on P and local criteria
Explanation:
Introduction / Context:
Sewer capacities must accommodate short-term peaks above the daily average. Designers apply a population-dependent peak factor (PF) to the average flow to obtain the design peak discharge for pipes and pumping stations.
Given Data / Assumptions:
Concept / Approach:
The general relationship is Q_max = PF * q. PF decreases with increasing P because larger populations “average out” individual usage variability. Additional allowances may be added for infiltration/inflow (I/I) based on local experience and standards.
Step-by-Step Solution:
Verification / Alternative check:
Compare against monitored flow data where available; confirm that resulting velocities meet minimum and maximum criteria under peak and low flows.
Why Other Options Are Wrong:
(a) Ignores peaking; (b) a fixed factor is not universally valid; (d) inverts the relationship and would underestimate the peak.
Common Pitfalls:
Using an inappropriate PF for population size; omitting infiltration allowances; not checking pump cycles or storage needs during extreme peaks.
Final Answer:
Q_max = PF * q, where PF is a peak factor dependent on P and local criteria
Discussion & Comments