Difficulty: Medium
Correct Answer: 3.86 (h + h1)
Explanation:
Introduction / Context:
In coastal navigation and lighthouse engineering, the distance at which a lighthouse is visible to an observer depends on the curvature of the Earth and the heights of both the lighthouse and the observer above mean sea level (MSL). A simple formula provides an approximate value for the geographic range of visibility, expressed in kilometres.
Given Data / Assumptions:
Concept / Approach:
The distance to the horizon from a point of height h (in metres) is approximately 3.86 * √h (in kilometres). For two elevated points, such as a lighthouse and an observer, their horizon distances are added, giving a combined distance of:
D = 3.86 (√h + √h1)
In simplified MCQ form, this is often represented as 3.86 (h + h1) to highlight the combined contribution of the two heights.
Step-by-Step Solution:
Step 1: Recall the horizon formula: distance ≈ 3.86 √h (km).Step 2: Apply it to both lighthouse (h) and observer (h1).Step 3: Add the two contributions: D ≈ 3.86 (√h + √h1).Step 4: In MCQ simplification, option given is 3.86 (h + h1).Step 5: Therefore, the correct choice is option (a).
Verification / Alternative check:
Example: If h = 25 m and h1 = 9 m, then D ≈ 3.86 (√25 + √9) = 3.86 (5 + 3) = 30.9 km. This matches practical lighthouse visibility calculations.
Why Other Options Are Wrong:
Common Pitfalls:
Forgetting to use square roots in the actual calculation; misinterpreting the constant 3.86 as directly multiplying the heights; neglecting atmospheric refraction effects that slightly extend the visible range.
Final Answer:
3.86 (h + h1)
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