Difficulty: Medium
Correct Answer: l = k √(cos 2α)
Explanation:
Introduction / Context:
Besides the clothoid (Euler spiral), the lemniscate is another transition curve used in geometric design for smooth variation of curvature. In polar coordinates, a classic lemniscate (of Bernoulli) provides a convenient mathematical description for layout and setting-out calculations in some highway/rail problems.
Given Data / Assumptions:
Concept / Approach:
The Bernoulli lemniscate has the polar equation r^2 = a^2 cos 2θ. In highway literature the same is often written as l^2 = k^2 cos 2α, where l is the radius vector from the origin on the initial tangent. Taking the positive square root for the relevant branch yields l = k √(cos 2α). This expresses how l varies with α and furnishes deflection relationships for setting out by angular methods.
Step-by-Step Solution:
Verification / Alternative check:
At α = 0, cos 2α = 1 → l = k (finite, maximum). At α = 45°, cos 90° = 0 → l = 0, consistent with the lemniscate reaching the origin at 45° from the tangent.
Why Other Options Are Wrong:
Linear sine/tangent or simple cosine forms without the square root do not match the defining equation r^2 ∝ cos 2θ and would yield incorrect geometry and stationing.
Common Pitfalls:
Forgetting the squared relation; confusing lemniscate with Euler spiral (where curvature varies linearly with arc length); using degrees vs radians incorrectly in computation.
Final Answer:
l = k √(cos 2α)
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