Comminution laws — identify Rittinger’s law: Which expression represents Rittinger’s crushing (grinding) law for specific energy in terms of characteristic feed and product sizes?
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AP/m = K * (1/Dp − 1/Df)
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BP/m = K * ln(Df/Dp)
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CP/m = K * (1/√Dp − 1/√Df)
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DNone of these
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EP/m is independent of size ratio for a given material
Answer
Correct Answer: P/m = K * (1/Dp − 1/Df)
Explanation
Introduction / Context:Three classical energy–size relations guide comminution analysis: Kick’s, Bond’s, and Rittinger’s laws. Each associates specific energy with a different function of the feed and product sizes and applies best in a particular size range. Rittinger’s law emphasises surface creation and is most applicable at fine sizes where new surface area dominates the energy requirement.
Given Data / Assumptions:
- P/m is specific power (energy per mass rate).
- Df and Dp denote characteristic feed and product sizes, respectively.
Concept / Approach:Rittinger’s law states that specific energy is proportional to new surface area produced, which for similar particle shapes scales with (1/Dp − 1/Df). Kick’s law relates energy to the natural logarithm of the size ratio ln(Df/Dp), suitable for coarse crushing. Bond’s law uses the inverse square-root term (1/√Dp − 1/√Df), widely applied in grinding mill design. Therefore, the correct expression for Rittinger is P/m = K * (1/Dp − 1/Df).
Step-by-Step Solution:
Recall surface-based dependence → inverse of size.Match to expression with 1/D terms.Select the option with (1/Dp − 1/Df).Verification / Alternative check:Textbook derivations equate energy to surface created with proportionality K, yielding the 1/D form; Bond’s and Kick’s distinct forms help cross-check.
Why Other Options Are Wrong:
- ln(Df/Dp): Kick’s law (coarse range).
- (1/√Dp − 1/√Df): Bond’s law (intermediate range).
- Independence from size ratio: contradicts all three laws.
Common Pitfalls:Forgetting which exponent belongs to which law; use the mnemonic Rittinger (1/D), Bond (1/√D), Kick (ln D).
Final Answer:P/m = K * (1/Dp − 1/Df)