Repair and evaluate the idempotent identity: In Boolean algebra, A + A = A (idempotent law for OR). Is this identity valid for all Boolean A?

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
The original stem was incomplete. Applying the Recovery-First Policy, we minimally repair it to the well-known idempotent identity A + A = A, which expresses that ORing a Boolean variable with itself yields the same variable. Idempotent laws (for both OR and AND) are among the most frequently used rules in algebraic simplification and K-map reasoning.


Given Data / Assumptions:

  • A is Boolean (0 or 1).
  • + denotes Boolean OR.
  • Goal: validate A + A = A for all A.


Concept / Approach:
An operation is idempotent if applying it multiple times does not change the result beyond the first application. For OR, combining A with itself does not introduce any new information beyond A, so the result equals A. There is a dual idempotent law for AND: A * A = A.


Step-by-Step Solution:

Case A = 0: 0 + 0 = 0, which equals A.Case A = 1: 1 + 1 = 1, which equals A.Since both cases match A, the identity holds universally.Thus, A + A simplifies to A in any Boolean expression.


Verification / Alternative check:
Truth table enumeration confirms the law instantly. In set-theoretic interpretation (union), X ∪ X = X mirrors the same idempotency, offering further intuition for the identity's correctness.


Why Other Options Are Wrong:

  • Incorrect: Contradicted by both truth table and set analogy.
  • Ambiguous as stated: After repair, the identity is precise and standard.
  • Cannot be determined: No further data is needed to validate an algebraic law.


Common Pitfalls:
Confusing with absorption (A + A*B = A) or domination (A + 1 = 1). While related, idempotency is distinct and should not be interchanged with those identities.


Final Answer:
Correct

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