Device choice: If a design requires a NAND gate, an AND function, and an inverter, would selecting a 7400 IC (quad 2-input NAND) be appropriate?

Introduction / Context:
The 7400 is a classic TTL IC containing four independent 2-input NAND gates. Knowing how to realize multiple logical functions using only NANDs is a standard skill because NAND is functionally complete: you can build any combinational logic, including NOT and AND, from NANDs alone.

Given Data / Assumptions:

• Available device: 7400 IC with four 2-input NAND gates.
• Required functions: one NAND, one AND, and one inverter (NOT).
• Assume unused gates are available on the same IC for composition.

Concept / Approach:
A NAND becomes an inverter by tying its inputs together (Y = NAND(A, A) = ~A). An AND function can be built by NAND followed by inversion: AND(A, B) = ~(~(A * B)) = invert(NAND(A, B)). Thus, a single 7400 provides enough gates to realize all three required behaviors simultaneously (subject to pin budgeting).

Step-by-Step Solution:

Verification / Alternative check:
Truth tables confirm that NAND with tied inputs realizes NOT, and NOT(NAND) realizes AND. The 7400's four gates typically provide enough resources for these combinations in small designs.

Why Other Options Are Wrong:

• Incorrect: Overlooks NAND functional completeness and common implementation patterns.
• Ambiguous as stated: The device and functions are clearly specified.
• Cannot be determined: No additional data is needed beyond basic gate composition rules.

Common Pitfalls:
Forgetting to budget gates: although one 7400 usually suffices, ensure you count how many inverters and NANDs your complete design needs to avoid running out of gates.

Final Answer:
Correct