Difficulty: Easy
Correct Answer: foreach (int j in i)
Explanation:
Introduction / Context:
Jagged arrays are arrays of arrays. To iterate every value, first enumerate each inner array, then enumerate its elements.
Given Data / Assumptions:
a is int[][] with rows of different lengths.i.
Concept / Approach:
The idiomatic nested foreach is: foreach (int[] i in a) { foreach (int j in i) { ... } }. This naturally handles different row lengths without index math.
Step-by-Step Solution:
i is an int[]).Inner loop: iterate values in i → foreach (int j in i).Print each j followed by a space, then write a newline per row.
Verification / Alternative check:
Run the code; it prints 6 1 4 3 on the first line and 9 2 7 on the second, matching the jagged structure.
Why Other Options Are Wrong:
a.Length is a scalar; you cannot foreach over an int.
Common Pitfalls:
Confusing rectangular array APIs (like GetUpperBound) with jagged arrays, which are just arrays whose elements are arrays.
Final Answer:
foreach (int j in i)
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