Video memory sizing: How much video RAM is required to support a resolution of 1024 × 768 at 24-bit true color (no overlays or extra buffers)?

Introduction / Context:
Sizing video memory for a given resolution and color depth is a classic calculation. Even though modern GPUs have abundant VRAM, understanding the framebuffer requirement remains useful for embedded systems, thin clients, and legacy hardware.

Given Data / Assumptions:

• Resolution: 1024 × 768 pixels.
• Color depth: 24 bits per pixel (true color), which equals 3 bytes per pixel.
• Only a single framebuffer is considered (no double buffering, Z-buffer, or textures).

Concept / Approach:

Video memory required for a single framebuffer equals pixel_count * bytes_per_pixel. Compute pixel_count, multiply by 3 bytes, then convert bytes to megabytes. Choose the smallest offered VRAM size that meets or exceeds this requirement from the options provided.

Step-by-Step Solution:

Verification / Alternative check:

Older graphics cards offering 2 MB could not do 1024 × 768 at 24-bit; cards with 4 MB were commonly specified for this mode, confirming the selection.

Why Other Options Are Wrong:

• 512KB / 1MB: Insufficient for the 2.25 MB requirement.
• 8MB: Works but is not the minimum required from the set; the question expects the adequate choice.
• None of the above: Incorrect because 4MB meets the need.

Common Pitfalls:

Confusing bits with bytes; forgetting overhead for additional buffers (which would further increase the requirement); assuming decimal megabytes instead of binary in legacy specs.

Final Answer:

4MB