Thin cylindrical shells with riveted joints: For a riveted cylindrical shell of diameter d and plate thickness t under internal pressure p, with joint efficiency η, the hoop (circumferential) stress is given by

Difficulty: Medium

Correct Answer: σh = p * d / (2 * t * η)

Explanation:


Introduction / Context:
Thin pressure vessels experience two principal membrane stresses: hoop (circumferential) and longitudinal. When a longitudinal riveted joint is present, its efficiency reduces the effective load-carrying thickness against hoop stress.



Given Data / Assumptions:

  • Thin cylinder (t ≪ d), uniform internal pressure p.
  • Riveted longitudinal joint with efficiency η (0 < η ≤ 1).
  • Membrane theory (neglecting bending and stress concentrations).


Concept / Approach:
For a seamless thin cylinder, hoop stress is σh = p * d / (2 * t). With a longitudinal joint of efficiency η, the effective resisting thickness is η * t, so the hoop stress increases to σh = p * d / (2 * η * t).



Step-by-Step Solution:

Start: σh(seamless) = p * d / (2 * t).Introduce joint efficiency: t_effective = η * t.Hence σh = p * d / (2 * t_effective) = p * d / (2 * t * η).Select the option matching this expression.


Verification / Alternative check:
Longitudinal stress for a seamless thin cylinder is σL = p * d / (4 * t). The presence of a circumferential joint would affect σL instead; here the longitudinal joint affects hoop stress as shown.



Why Other Options Are Wrong:

  • p * d / (4 * t * η) corresponds to longitudinal stress with joint efficiency, not hoop stress.
  • p * d / (t * η) and 2 * p * d / (t * η) overstate the stress by missing the factor 2 or adding an extra 2.
  • p / (2 * t * η * d) has wrong dependence on diameter.


Common Pitfalls:
Mixing hoop and longitudinal stress formulas; always note the factor 2 difference.



Final Answer:
σh = p * d / (2 * t * η)

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