Difficulty: Medium
Correct Answer: δ = 8 * W * D^3 * n / (C * d^4)
Explanation:
Introduction / Context:
Close-coiled helical springs store energy primarily by twisting of the wire. The load–deflection relation links geometry (D, d, n) and material shear modulus to the axial compliance.
Given Data / Assumptions:
Concept / Approach:
Each coil behaves like a torsion bar of circular section. Summing angular twist over n coils and converting to axial deflection yields the well-known expression δ = 8 * W * D^3 * n / (C * d^4).
Step-by-Step Solution:
Verification / Alternative check:
Dimensional check: δ has units of length; numerator W * D^3 * n divided by C * d^4 (stress per shear-strain scale) yields length.
Why Other Options Are Wrong:
Common Pitfalls:
Using E instead of C (G); mixing up D (mean diameter) with radius; forgetting the power d^4 in the denominator.
Final Answer:
δ = 8 * W * D^3 * n / (C * d^4)
Discussion & Comments