Hall dimensions — The length is (4/3) times its breadth. If the area is 300 sq m, find the difference (length − breadth).

Introduction / Context:
Relate length and breadth via a given ratio and use area to solve for actual dimensions. The subtraction then yields the requested difference.

Given Data / Assumptions:

• L = (4/3)B
• Area A = 300 sq m

Concept / Approach:
A = L * B = (4/3)B^2 ⇒ solve B from B^2 = (3/4)A. Then compute L and the difference L − B.

Step-by-Step Solution:
B^2 = (3/4) * 300 = 225 ⇒ B = 15 mL = (4/3)*15 = 20 mDifference = 20 − 15 = 5 m

Verification / Alternative check:
Area check: 20 * 15 = 300 ✔

Why Other Options Are Wrong:
15 m is a side, not the difference; 4 m and 3 m are distractors; “None” is false.

Common Pitfalls:
Taking 4/3 of area instead of of breadth, or forgetting to take the square root.

Final Answer:
5 meters