Half-bridge inverter output frequency vs. device gating frequency A single-phase half-bridge inverter gates each thyristor at a frequency f with 180° conduction (no PWM). What is the fundamental output frequency delivered to the load?
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A2 f
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Bf
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C0.5 f
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D0.25 f
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E—
Answer
Correct Answer: f
Explanation
Introduction / Context:In a half-bridge inverter, two complementary switches (thyristors or transistors) connect the output alternately to +Vdc/2 and −Vdc/2. The relationship between the gating frequency per device and the fundamental output frequency is essential for designing control and filters.
Given Data / Assumptions:
- Each device conducts for half a cycle (180° conduction).
- No PWM or modulation; simple square-wave operation.
- Complementary gating; dead-time negligible for this ideal discussion.
Concept / Approach:
When the top device turns on, the output is +Vdc/2 for half a period; when the bottom device turns on, the output is −Vdc/2 for the next half period. Each device turns on once per output cycle. Therefore, the per-device gating repetition rate equals the output fundamental frequency.
Step-by-Step Solution:
Define device gating frequency per switch = f.One full output cycle requires one ON of the top and one ON of the bottom device.Thus the output fundamental frequency f_out = f.Verification / Alternative check:
Waveform analysis: the square wave has a period equal to the time between consecutive ON instants of the same switch, identical to the gating period.
Why Other Options Are Wrong:
(a) Implies two device turns per period per device, which is not the 180° scheme. (c) and (d) contradict the basic two-step per cycle operation.
Common Pitfalls:
Confusing total switching events per cycle (two across both devices) with per-device gating frequency.
Final Answer:
f