Serial loading into a 5-bit shift register (right-most bit first) Bits 11001 are shifted in (LSB first) to a 5-bit parallel-output shift register whose initial state is 01110. After three clock pulses, what pattern is stored?

Introduction / Context:
Shift registers are fundamental sequential circuits. Problems often specify the order of serial data (for example, “right-most bit first”) and the direction of shifting. Careful tracking of each clock edge avoids off-by-one errors.

Given Data / Assumptions:

• 5-bit register initial contents: 0 1 1 1 0 (MSB→LSB).
• Incoming serial pattern: 11001, right-most bit first → input sequence = 1, 0, 0, 1, 1.
• On each clock the register shifts to the right; the serial input enters the MSB.

Concept / Approach:
Apply one clock at a time, moving each bit right by one position. The value entering the MSB is the next serial input bit. After the specified number of clocks, read out the five stored bits.

Step-by-Step Solution:
Initial: 0 1 1 1 0.Clock 1 (in=1): 1 0 1 1 1.Clock 2 (in=0): 0 1 0 1 1.Clock 3 (in=0): 0 0 1 0 1.Stored pattern after 3 clocks (MSB→LSB): 0 0 1 0 1 → 00101.

Verification / Alternative check:
Repeat the sequence with a quick table of states per clock; both methods give 00101 after the third pulse.

Why Other Options Are Wrong:
01110: original state, ignores shifting.00001 / 00110: off-by-one or wrong input ordering.11101: does not match the right-shift with given inputs.

Common Pitfalls:
Confusing “right-most bit first” with least-significant bit last, or assuming the serial input enters the LSB instead of the MSB for a right-shifting register.

Final Answer:
00101