Difficulty: Easy
Correct Answer: Q1 - 2 = dU + W1 - 2
Explanation:
Introduction / Context:The general gas energy equation is simply the first law of thermodynamics written for a closed system. It states that heat added to a system is used to change its internal energy and to perform boundary work.
Given Data / Assumptions:
Concept / Approach:
The first law for a closed system is written as Q1–2 = ΔU + W1–2. Here, ΔU is U2 − U1 and W1–2 is boundary work (area under the p–v curve). The relation is independent of path specifics; it simply balances energy.
Step-by-Step Solution:
State the first law for a closed system: Q_in − Q_out = ΔU + W (by system).For a single net heat term Q1–2 (positive when supplied), write Q1–2 = ΔU + W1–2.Interpret physically: supplied heat splits into stored energy (internal) and mechanical output (work).Check units consistency if using heat units for all terms.Verification / Alternative check:
Special cases: For an adiabatic process Q1–2 = 0 → W1–2 = −ΔU. For an isochoric process W1–2 = 0 → Q1–2 = ΔU. Both obey the same master equation.
Why Other Options Are Wrong:
Minus signs or algebraic operations like division or multiplication do not reflect energy conservation. The equality must be additive with proper signs.
Common Pitfalls:
Sign convention confusion (work by vs. on the system); forgetting to include boundary work only (not shaft work in closed simple systems unless explicitly present).
Final Answer:
Q1 - 2 = dU + W1 - 2
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