$\frac{3}{2} \times \frac{11}{5} \div \left( \frac{25}{44} \times \frac{11}{5} \right) \div \frac{33}{15} = x$
Aptitude
Simplification
Difficulty: Medium
Choose an option
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A$\frac{1}{2}$
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B$\frac{2}{3}$
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C$\frac{126}{125}$
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D$5 \frac{101}{125}$
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ENone of these
Answer
Correct Answer: None of these
Explanation
### Concept & Strategy
This simplification problem strictly follows the BODMAS rule. Operations inside parentheses (brackets) must be executed first, followed by continuous division from left to right by multiplying with the reciprocal.
### Step-by-Step Solution
* **Given:** $\frac{3}{2} \times \frac{11}{5} \div \left( \frac{25}{44} \times \frac{11}{5} \right) \div \frac{33}{15}$
* **Solve the expression inside the bracket:**
* $\frac{25}{44} \times \frac{11}{5} = \frac{5 \times 5}{4 \times 11} \times \frac{11}{5} = \frac{5}{4}$
* **Substitute back and convert division to multiplication:**
* $\frac{3}{2} \times \frac{11}{5} \div \frac{5}{4} \div \frac{33}{15}$
* Replace division signs with multiplication by inverting the fractions:
* $\frac{3}{2} \times \frac{11}{5} \times \frac{4}{5} \times \frac{15}{33}$
* **Simplify the terms:**
* Notice that $\frac{3 \times 11}{33} = \frac{33}{33} = 1$, so they cancel out completely.
* Remaining terms: $\frac{1}{2} \times \frac{1}{5} \times \frac{4}{5} \times 15$
* $\frac{4 \times 15}{2 \times 25} = \frac{60}{50}$
* $\frac{60}{50} = \frac{6}{5}$
* **Convert to mixed fraction:**
* $\frac{6}{5} = 1 \frac{1}{5}$
### Exam Strategy & Shortcut
Convert all division signs to multiplication immediately after solving brackets. Write it as one long chain of multiplication: $\frac{3}{2} \times \frac{11}{5} \times \frac{4}{5} \times \frac{15}{33}$. Cross-cancel aggressively (like $3 \times 11$ and $33$) before doing any actual large multiplication.
### Common Pitfall
A frequent error in chained division ($A \div B \div C$) is treating it as $A \div (B \div C)$. Division is left-associative. Always process it left-to-right, or better yet, convert all divisions to multiplication by the reciprocal to avoid ambiguity entirely.
### Final Answer
**Therefore, the correct answer is None of these.**