**Direction:** Read the following information carefully and answer the questions given below. Eight persons A, B, C, D, E, F, G and H are born in four different years viz., 1964, 1977, 1982 and 1991 and also in two different months viz., June and July but not necessary in the same order. All they are wearing eight different watches namely Noise, Omega, Citizen, Casio, Tissot, Timex, Titan and Amazfit. No two persons born in same month of a year. Age of the persons is calculated as on December 2020. Each year two persons were born in two different months. Months are not considered for age calculation. The person who wears Noise born immediately before F. F was born in the month which has 30 days. The sum of the ages of B and the one who wears Omega is equal to perfect square of a number. There are only three persons born between E and the one who wears Casio. D was not born in odd numbered year. More than two persons born between H and one who wears Tissot. As many persons born between A and the one who wears Timex is same as the persons born after the one who wears Citizen. There are two persons born between D and the one who wears Titan. Age of the one who wears Casio is not a prime number but born in one of the months before the one who wears Citizen. There are only two persons born between the one who wears Casio and the one wears Omega. Only one person born between B and the one who wears Titan, who was not born in the year 1964. C and the one who wears Tissot are born in different month. A was born immediately after the F. H does not like Timex. F was not born immediately before or after the one who wear Citizen. Four of the following alike in a certain way and thus form a group. Which of the following one that does not belong to the group?

### Concept & Logic In puzzles involving months and years, odd-one-out questions typically group individuals based on whether they were born in a month with 30 days vs 31 days, or if they were born in a leap year vs non-leap year. ### Step-by-Step Solution 1. **Calculate Ages (Base Year 2020):** * 1964 $\rightarrow$ 56 years * 1977 $\rightarrow$ 43 years * 1982 $\rightarrow$ 38 years * 1991 $\rightarrow$ 29 years 2. **Map the Chronological Slots (June is 30 days, July is 31):** * 1: 1964 June, 2: 1964 July * 3: 1977 June, 4: 1977 July * 5: 1982 June, 6: 1982 July * 7: 1991 June, 8: 1991 July 3. **Apply Core Constraints:** * B + Omega = Perfect Square. Possible ages are 56, 43, 38, 29. Only $43 + 38 = 81$ ($9^2$) forms a perfect square. So, B and Omega belong to 1977 and 1982. * F is born in a 30-day month (June). * Block: [Noise, F, A] (Noise immediately before F, A immediately after F). F must be in June of 1977, 1982, or 1991 so Noise can be in July of the preceding year. 4. **Deduce Positions:** * Testing F in 1977 June (Slot 3): Noise is 1964 July (Slot 2), A is 1977 July (Slot 4). * Since 1977 is full (F and A), B must be born in 1982 (Slots 5 or 6). Thus, the person wearing Omega is born in 1977. Since A wears Titan (deduced later), F (Slot 3) wears Omega. * "Casio not prime" & "Two persons between Casio and Omega": Omega is Slot 3, meaning Casio is Slot 6 (1982 July, age 38, not a prime number). B is Slot 6 wearing Casio. * "Three persons between E and Casio": Casio is Slot 6, so E is Slot 2 (wearing Noise). * "D not in odd year" & "Two persons between D and Titan": D must be 1964 June (Slot 1). Titan is Slot 4 (worn by A). * "One person between B and Titan": B(6) and Titan(4). This matches perfectly. * "Casio before Citizen": Citizen must be Slot 7 or 8. * "0 persons between A and Timex" = "0 persons after Citizen": A is Slot 4. If Timex is Slot 5, there are 0 persons between them. This means Citizen must be Slot 8 (so 0 persons are after it). * "H does not like Timex" & ">2 persons between H and Tissot": H must be Slot 7. Tissot is Slot 1. * "C and Tissot in different months": Tissot is June. C must be July (Slot 8). C wears Citizen. * G fills Slot 5. H wears Amazfit. 5. **Final Arrangement:** * 1 (1964 Jun): D, Tissot (Age 56) * 2 (1964 Jul): E, Noise (Age 56) * 3 (1977 Jun): F, Omega (Age 43) * 4 (1977 Jul): A, Titan (Age 43) * 5 (1982 Jun): G, Timex (Age 38) * 6 (1982 Jul): B, Casio (Age 38) * 7 (1991 Jun): H, Amazfit (Age 29) * 8 (1991 Jul): C, Citizen (Age 29) 6. **Answer the Question:** Let us evaluate the birth months for the given options: * D $\rightarrow$ June (30 Days) * F $\rightarrow$ June (30 Days) * H $\rightarrow$ June (30 Days) * C $\rightarrow$ July (31 Days) * G $\rightarrow$ June (30 Days) All individuals except C were born in June. ### Exam Strategy & Shortcut Whenever a reasoning puzzle asks for the "odd one out" among 5 options and the data includes exactly two distinct categories (like June/July or Even/Odd years), simply list the categories for the options. The one that stands alone is the answer. ### Common Pitfall Wasting time checking complex attributes like prime ages or watch brands when the simplest binary split (June vs. July) provides the definitive answer. ### Final Answer Therefore, the correct answer is **C**.