Linked averages for overlapping triplets: Of four numbers a, b, c, d, the average of the first three is 15, the average of the last three is 16, and the last number d is 19. Find the first number a.

Difficulty: Easy

Correct Answer: 16

Explanation:


Introduction / Context:
When averages of overlapping groups are known, sums can be equated to determine individual elements.

Given Data / Assumptions:

  • (a + b + c)/3 = 15
  • (b + c + d)/3 = 16
  • d = 19


Concept / Approach:
Compute sums from averages, eliminate common parts, and solve for the unknown a.

Step-by-Step Solution:

a + b + c = 45b + c + d = 48Substitute d = 19 to get b + c = 29Therefore a = 45 - (b + c) = 45 - 29 = 16


Verification / Alternative check:
Check last three: b + c + d = 29 + 19 = 48, average = 16. Works.

Why Other Options Are Wrong:

  • 15, 18, 19: They do not satisfy both average relations simultaneously.


Common Pitfalls:
Incorrectly averaging the two averages instead of using sums.

Final Answer:

16

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