Three linked numbers: The first number is twice the second and half of the third. If the average of the three numbers is 56, find the numbers in order (first, second, third).

Difficulty: Easy

Correct Answer: 48, 24, 96

Explanation:


Introduction / Context:
Ratio based constraints allow representation of all numbers in a single variable and then direct solution using the average.

Given Data / Assumptions:

  • First = twice the second
  • First = half of the third
  • Average of three = 56


Concept / Approach:
Let the second be x. Then first = 2x and third = 4x. Use the average to solve x.

Step-by-Step Solution:

(2x + x + 4x)/3 = 567x/3 = 56x = 56 * 3 / 7 = 24Numbers: 2x = 48, x = 24, 4x = 96


Verification / Alternative check:
Average = (48 + 24 + 96)/3 = 168/3 = 56. Correct.

Why Other Options Are Wrong:

  • Other orders fail the given relationships and the computed average simultaneously.


Common Pitfalls:
Assigning the variable to the wrong number or reversing the given relationships.

Final Answer:

48, 24, 96

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