8051 direct addressing — does the instruction 'MOV 23H, A' copy the Accumulator to internal RAM address 23H? Decide whether this statement about direct-address destination is correct.

Difficulty: Easy

Correct Answer: True

Explanation:


Introduction / Context:
Addressing modes determine where data moves in a single cycle. In the 8051, direct addressing targets a specific internal RAM or SFR address. Understanding what range maps to internal RAM vs SFRs prevents subtle bugs.


Given Data / Assumptions:

  • Instruction: MOV 23H, A
  • Address 23H is within 00H–7FH (lower internal RAM in a base 8051)
  • Accumulator A contains a byte to store


Concept / Approach:
Direct destinations in the lower 128 bytes (00H–7FH) reference internal RAM. The bit-addressable area is 20H–2FH, but byte writes to 23H still write the full byte. SFRs occupy 80H–FFH, so 23H is not an SFR address on a basic 8051.


Step-by-Step Solution:

Check address range: 23H < 80H ⇒ internal RAMOperation form: MOV direct, A ⇒ store A into byte at directTherefore: byte at RAM[23H] ← A


Verification / Alternative check:
Cross-reference the 8051 memory map: SFRs start at 80H; lower 128 is internal RAM, so the instruction is a valid byte move to RAM address 23H.


Why Other Options Are Wrong:

  • False: contradicts the memory map.
  • Writes to SFR 23H: SFRs are at 80H–FFH.
  • Only bit transfer: MOV writes a full byte.
  • Requires @R0/@R1: direct addressing does not require indirect registers.


Common Pitfalls:

  • Confusing bit-addressable region with bit-only access; bytes are still writable.


Final Answer:
True

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