In digital electronics, which simple flip-flop based circuit can be used to divide a clock frequency by a factor of two?

Difficulty: Easy

Correct Answer: A toggle (T) flip-flop driven by the clock, with its Q output providing a clock at half the input frequency

Explanation:


Introduction / Context:
Frequency division is a basic requirement in many hardware designs. For example, a microcontroller may need a slower internal clock derived from a faster external clock, or a communication interface may need to produce timing signals at different rates. The simplest and most common case is dividing a clock frequency by two. This question asks which flip-flop based circuit provides a clean and reliable divide by two function in digital electronics.



Given Data / Assumptions:

  • We have a periodic clock signal that toggles between logic 0 and logic 1.
  • We want an output that has exactly half the frequency of the input clock.
  • The output must be a stable square wave suitable for use as a clock.
  • Standard flip-flop types such as T, JK configured as T, or D with feedback are available.


Concept / Approach:
A toggle flip-flop changes its output state on each active clock edge when its toggle input is enabled. If the flip-flop starts at logic 0, then on the first clock edge Q becomes 1, on the second edge Q becomes 0 again, and so on. In other words, it completes one full cycle 0 to 1 to 0 for every two input clock cycles. That means the output frequency is exactly half the input clock frequency. The same behaviour can be achieved with a JK flip-flop with J and K tied high or a D flip-flop whose inverted output is fed back to the D input.



Step-by-Step Solution:
Step 1: Select a toggle capable flip-flop, such as a T flip-flop or JK flip-flop with J and K both tied to logic 1.Step 2: Connect the external clock signal to the clock input of the flip-flop.Step 3: Ensure the toggle input is enabled so that the flip-flop changes state on each active clock edge.Step 4: Observe that for every two input clock pulses, the Q output completes one full cycle, so its frequency is half that of the input.Step 5: Use the Q output as the divided by two clock in the rest of the circuit.


Verification / Alternative check:
You can verify this behaviour by drawing a timing diagram. Mark the input clock transitions and then show Q toggling at each active edge. You will see that Q stays high for one full clock period and then low for one full clock period, so its period is twice that of the input clock. The duty cycle is close to fifty percent, which is ideal for a clock. This confirms that a toggle flip-flop is a natural divide by two circuit.



Why Other Options Are Wrong:
Option B is incorrect because a monostable multivibrator produces a single pulse for each trigger and does not inherently divide frequency by two in a stable, continuous way. Option C is wrong because an AND gate with both inputs tied to the clock simply reproduces the clock, not a divided version. Option D describes a four stage ring counter, which would divide the frequency by four rather than by two.



Common Pitfalls:
A common mistake is to assume that any flip-flop will automatically divide the frequency, but the configuration matters. A D flip-flop only divides by two when its D input is driven by the inverted Q output, creating a toggle behaviour. Another pitfall is to overlook setup and hold time requirements, which can cause unreliable toggling if not met. Designers must also ensure that the input clock edges are clean and free of glitches to avoid spurious toggles.



Final Answer:
The correct circuit is a toggle (T) flip-flop driven by the clock, with its Q output providing a clock at half the input frequency.


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